IIT JAM Exam > IIT JAM Questions > From the set of 10 numbers {1, 2,...,10} thre...
Start Learning for Free
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is
- a)1/40
- b)1/20
- c)3/10
- d)3/80
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
From the set of 10 numbers {1, 2,...,10} three numbers are selected at...
Problem:
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40 b)1/20 c)3/10 d)3/80. The correct answer is option 'A'. Explain this answer.
Solution:
We are given a set of 10 numbers: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. We need to select three numbers from this set without replacement and find the probability that their sum is 9.
Total Possible Outcomes:
To calculate the total possible outcomes, we need to find the total number of ways we can select three numbers from the given set of 10 numbers. This can be calculated using the combination formula.
Number of ways to select 3 numbers from 10 = 10C3 = (10!)/(3!(10-3)!) = 120
Therefore, the total number of possible outcomes is 120.
Favorable Outcomes:
To calculate the favorable outcomes, we need to find the number of ways we can select three numbers from the given set of 10 numbers such that their sum is 9.
We can find the favorable outcomes by listing all the possible combinations that satisfy the condition.
The possible combinations that sum up to 9 are:
1, 2, 6
1, 3, 5
2, 3, 4
Therefore, there are 3 favorable outcomes.
Probability:
The probability of an event is defined as the ratio of the number of favorable outcomes to the number of total possible outcomes.
Probability = (Number of favorable outcomes) / (Number of total possible outcomes)
Plugging in the values, we get:
Probability = 3/120 = 1/40
Therefore, the probability that the sum of the selected numbers is 9 is 1/40.
Conclusion:
The correct answer is option 'A' (1/40).
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40 b)1/20 c)3/10 d)3/80. The correct answer is option 'A'. Explain this answer.
Solution:
We are given a set of 10 numbers: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. We need to select three numbers from this set without replacement and find the probability that their sum is 9.
Total Possible Outcomes:
To calculate the total possible outcomes, we need to find the total number of ways we can select three numbers from the given set of 10 numbers. This can be calculated using the combination formula.
Number of ways to select 3 numbers from 10 = 10C3 = (10!)/(3!(10-3)!) = 120
Therefore, the total number of possible outcomes is 120.
Favorable Outcomes:
To calculate the favorable outcomes, we need to find the number of ways we can select three numbers from the given set of 10 numbers such that their sum is 9.
We can find the favorable outcomes by listing all the possible combinations that satisfy the condition.
The possible combinations that sum up to 9 are:
1, 2, 6
1, 3, 5
2, 3, 4
Therefore, there are 3 favorable outcomes.
Probability:
The probability of an event is defined as the ratio of the number of favorable outcomes to the number of total possible outcomes.
Probability = (Number of favorable outcomes) / (Number of total possible outcomes)
Plugging in the values, we get:
Probability = 3/120 = 1/40
Therefore, the probability that the sum of the selected numbers is 9 is 1/40.
Conclusion:
The correct answer is option 'A' (1/40).
|
Explore Courses for IIT JAM exam
|
|
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer?
Question Description
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer?.
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer?.
Solutions for From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM.
Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
Here you can find the meaning of From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer?, a detailed solution for From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40b)1/20c)3/10d)3/80Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice IIT JAM tests.
|
|
Explore Courses for IIT JAM exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup